如何在 Python Turtle 的 Tic-Tac-Toe 游戏中交替 2 个玩家？

Question

我正在上计算机科学课，我们的第一个 Python 项目（海龟）是一个小井字游戏。该项目已接近完成，但我正在努力弄清楚如何在 2 个玩家之间切换，请告诉我我是如何处理这个问题的，因为我仍在学习。

我尝试使用一个用于 for 循环的变量，其中值等于 0，然后每次玩家移动时，它都会为该值添加+1，因此理论上，每次他们移动时，它都会添加1，然后 for 循环将不成立，然后切换到另一个玩家的另一个 for 循环。我现在意识到这些都没有任何意义，也不会起作用。看起来是这样的：

if current_player == "o" or current_player == "O":
    while current_player == "o" or current_player == "O":
        alternate_turn = 0
        while alternate_turn == 0:
            user_input = int(input("Type in a number where O would like to move: "))
            if user_input == 1 :
                goto(-134,140)
                alternate_turn = alternate_turn + 1

每次我运行这个，它都会崩溃。所以我现在陷入了最初的困境：

#If the user said "x", code checks for to see if true then runs commands for "x"
if current_player == "x" or current_player == "X" :
    while current_player == "x" or current_player == "X":
        user_input = int(input("Type in a number where X would like to move: "))

#If user said "o", code checks to see if true then runs commands for "o"
if current_player == "o" or current_player == "O":
    while current_player == "o" or current_player == "O":
        user_input = int(input("Type in a number where O would like to move: "))

这是一个可重现的示例：

#Ask user for input on who goes first
user_select = (input("Who is playing first?(X or O?): "))

#Whatever the user said for user_select, it is stored as the current_player
current_player = user_select

#If the user said "x", code checks for to see if true then runs following commands
if current_player == "x" or current_player == "X" :
    while current_player == "x" or current_player == "X":
        user_input = int(input("Type in a number where X would like to move: "))
#If user said "o", code checks to see if true then runs commands for "o"
if current_player == "o" or current_player == "O":
    while current_player == "o" or current_player == "O":
        user_input = int(input("Type in a number where O would like to move: "))

我非常不确定下一步该做什么。我尝试过寻找其他解决方案，但是，它们似乎都不适合我的代码（也许是因为它们不适合我的代码）。我想要实现的是，当它要求“X”或“O”输入时，其中任何一个都会输入一个他们将移动的数字，然后它会转到下一个玩家，然后在那之后做同样的事情，直到平局或有人获胜。我愿意接受任何解决此问题的方法，因为截止日期是本周五。谢谢您，如果我的帖子有点不清楚，我深表歉意，因为这是我第一次发帖。

Answer 1

您的程序可能会崩溃，因为它将永远运行。在循环中的任何时刻都不会更改播放器。另外，您不需要

while

。我看到的另一个问题是，你试图变得过于自由。 “X”或“x”表示你连自己的球员是什么样的都不知道。当然，玩家可能能够输入“x”或“X”，但这与识别玩家没有任何关系。想象一下，如果这是国际象棋。你真的要检查棋盘一侧的每一个棋子，看看它是否是玩家一号吗？

if current_player == "x" or current_player == "X" :
    while current_player == "x" or current_player == "X":
        user_input = int(input("Type in a number where X would like to move: "))

这是切换玩家方法的一个非常基本的示例。我换球员的地方可能不适合你。我不知道你的代码是什么，这只是一个最小的例子。简而言之：您必须更改

current_player

才能更改

current_player

。

player_one = input("Input Player One Name: ")
player_two = input("Input Player Two Name: ")

current_player = player_one

while True:
    if current_player == player_one:
        user_input = int(input("Type in a number where X would like to move: "))
        current_player = player_two

    elif current_player == player_two:
        user_input = int(input("Type in a number where O would like to move: "))
        current_player = player_one

    else:
        raise ValueError('unrecognized player')