对于一个班级项目，我和我的队友将编写井字游戏程序。到目前为止，这就是我们所拥有的。我们所有人都有0位使用python的经验，这是我们第一次真正使用python进行编码。
import random
import colorama
from colorama import Fore, Style
print(Fore.LIGHTWHITE_EX + "Tic Tac Toe - Below is the key to the board.")
Style.RESET_ALL
player_1_pick = ""
player_2_pick = ""
if (player_1_pick == "" or player_2_pick == ""):
if (player_1_pick == ""):
player_1_pick = "Player 1"
if (player_2_pick == ""):
player_2_pick = "Player 2"
else:
pass
board = ["_"] * 9
print(Fore.LIGHTBLUE_EX + "0|1|2\n3|4|5\n6|7|8\n")
def print_board():
for i in range(0, 3):
for j in range(0, 3):
if (board[i*3 + j] == 'X'):
print(Fore.RED + board[i*3 + j], end = '')
elif (board[i*3 + j] == 'O'):
print(Fore.BLUE + board[i*3 + j], end = '')
else:
print(board[i*3 + j], end = '')
print(Style.RESET_ALL, end = '')
if j != 2:
print('|', end = '')
print()
print_board()
while True:
x = input('Player 1, pick a number from 0-8: ') #
x = int(x)
board[x] = 'X'
print_board()
o = input('Player 2, pick a number from 0-8:')
o = int(o)
board[o] = 'O'
print_board()
answer = raw_input("Would you like to play it again?")
if answer == 'yes':
restart_game()
else:
close_game()
WAYS_T0_WIN = ((0,1,2)(3,4,5)(6,7,8)(0,3,6)(1,4,7)(2,5,8)(0,4,8)(2,4,6))
[我们被困在如何让程序检测某人何时赢得游戏，然后将其打印为“ You won！”。并让程序检测何时是领带，并打印“这是领带！”。我们已经在整个互联网上寻找解决方案，但是它们都不起作用，我们无法理解其中的说明。没用问老师，因为他们不了解python或如何编码。
我已经更改了您的代码，首先是“保存玩家的选择”，然后是“检查玩家是否赢了并打破循环”：
import random
import colorama
from colorama import Fore, Style
print(Fore.LIGHTWHITE_EX + "Tic Tac Toe - Below is the key to the board.")
Style.RESET_ALL
player_1_pick = ""
player_2_pick = ""
if (player_1_pick == "" or player_2_pick == ""):
if (player_1_pick == ""):
player_1_pick = "Player 1"
if (player_2_pick == ""):
player_2_pick = "Player 2"
else:
pass
board = ["_"] * 9
print(Fore.LIGHTBLUE_EX + "0|1|2\n3|4|5\n6|7|8\n")
def print_board():
for i in range(0, 3):
for j in range(0, 3):
if (board[i*3 + j] == 'X'):
print(Fore.RED + board[i*3 + j], end = '')
elif (board[i*3 + j] == 'O'):
print(Fore.BLUE + board[i*3 + j], end = '')
else:
print(board[i*3 + j], end = '')
print(Style.RESET_ALL, end = '')
if j != 2:
print('|', end = '')
print()
def won(choices):
WAYS_T0_WIN = [(0,1,2), (3,4,5), (6,7,8), (0,3,6), (1,4,7), (2,5,8), (0,4,8), (2,4,6)]
for tpl in WAYS_T0_WIN:
if all(e in choices for e in tpl):
return True
return False
print_board()
turn = True
first_player_choices = []
second_player_choices = []
while True:
if turn:
x = input('Player 1, pick a number from 0-8: ') #
x = int(x)
if board[x] == '_':
board[x] = 'X'
first_player_choices.append(x)
turn = not turn
print_board()
if won(first_player_choices):
print('Player 1 won!')
break
else:
print('Already taken! Again:')
continue
else:
o = input('Player 2, pick a number from 0-8: ') #
o = int(o)
if board[o] == '_':
board[o] = 'O'
second_player_choices.append(o)
turn = not turn
print_board()
if won(second_player_choices):
print('Player 2 won!')
break
else:
print('Already taken! Again:')
continue
# answer = input("Would you like to play it again?")
# if answer == 'yes':
# restart_game()
# else:
# close_game()
我还添加了一个条件来检查是否已选择玩家！顺便说一句，您可以做得更好。 ：）
EDIT：我的答案在空格中有一个小问题，我在编辑中解决了。现在您可以直接将其复制到py文件中并运行它！
[首先，您需要一个条件，不允许两次分配相同的空间，例如，在测试运行时，我可以输入所需的任意数量的空间3，例如，它不会阻止我。您需要对此进行某种检查。
第二，对于实际的获胜系统，您已经很容易了，因为您已经拥有所有获胜游戏的坐标，我建议遵循以下原则：
def checkwin(team):
for i in WAYS_TO_WIN:
checked = False
while not checked:
k = 0
for j in i:
if board[j] == team:
k+=1
if k == 3:
return True
checked = True
这种方法检查是否有任何座标具有所有三个坐标。您可能需要调整此代码，但这看起来像一个解决方案。
注意：我仍然是编码的初学者，偶然发现了您的线程，这不一定是可行的解决方案