我正在编写井字棋代码，但有点卡住了！ 用户输入一个位置，如果输入的位置为空（其位置有一个数字），我想将数字更改为 X 或 O。
在下面的代码中，我创建了一个字典，其中的键代表棋盘上的位置。
我可以调用我字典中key的value的内容来代替实际的value吗？例如如果输入为 0，我想使用
display_list[0][0]display_list[0][0]row_1 = [0,1,2]
row_2 = [3,4,5]
row_3 = [6,7,8]
display_list = [row_1, row_2, row_3]
def valid_position():
positions = {'0':display_list[0][0],
'1':display_list[0][1],
'2':display_list[0][2],
'3':display_list[1][0],
'4':display_list[1][1],
'5':display_list[1][2],
'6':display_list[2][0],
'7':display_list[2][1],
'8':display_list[2][2]
}
x = str(user_input()) # This is a user input from 0-8
if x == str(positions[x]):
display_list[..][..] = 'X'
如果你想解决这个问题，你可以添加另一个字典来获得你想要的输出，例如：
positions_labels = {'0':'display_list[0][0]',
'1':'display_list[0][1]',
'2':'display_list[0][2]',
'3':'display_list[1][0]',
'4':'display_list[1][1]',
'5':'display_list[1][2]',
'6':'display_list[2][0]',
'7':'display_list[2][1]',
'8':'display_list[2][2]'
}
所以无论您想要位置使用
positions_labels[x]评论补充： 如果您想评估字符串内容（获取其值），您可以按照链接中的方式进行操作
就我个人而言，这不是编写 Tic Tac Toe 的好方法。如果我是你，我会使用由数组和 if 语句组成的不同方法。
这就是我的做法（请随意继续您的方式！:)
# Function to print Tic Tac Toe
def print_tic_tac_toe(values):
print("\n")
print("\t | |")
print("\t {} | {} | {}".format(values[0], values[1], values[2]))
print('\t_____|_____|_____')
print("\t | |")
print("\t {} | {} | {}".format(values[3], values[4], values[5]))
print('\t_____|_____|_____')
print("\t | |")
print("\t {} | {} | {}".format(values[6], values[7], values[8]))
print("\t | |")
print("\n")
# Function to print the score-board
def print_scoreboard(score_board):
print("\t--------------------------------")
print("\t SCOREBOARD ")
print("\t--------------------------------")
players = list(score_board.keys())
print("\t ", players[0], "\t ", score_board[players[0]])
print("\t ", players[1], "\t ", score_board[players[1]])
print("\t--------------------------------\n")
# Function to check if any player has won
def check_win(player_pos, cur_player):
# All possible winning combinations
soln = [[1, 2, 3], [4, 5, 6], [7, 8, 9], [1, 4, 7], [2, 5, 8], [3, 6, 9], [1, 5, 9], [3, 5, 7]]
# Loop to check if any winning combination is satisfied
for x in soln:
if all(y in player_pos[cur_player] for y in x):
# Return True if any winning combination satisfies
return True
# Return False if no combination is satisfied
return False
# Function to check if the game is drawn
def check_draw(player_pos):
if len(player_pos['X']) + len(player_pos['O']) == 9:
return True
return False
# Function for a single game of Tic Tac Toe
def single_game(cur_player):
# Represents the Tic Tac Toe
values = [' ' for x in range(9)]
# Stores the positions occupied by X and O
player_pos = {'X':[], 'O':[]}
# Game Loop for a single game of Tic Tac Toe
while True:
print_tic_tac_toe(values)
# Try exception block for MOVE input
try:
print("Player ", cur_player, " turn. Which box? : ", end="")
move = int(input())
except ValueError:
print("Wrong Input!!! Try Again")
continue
# Sanity check for MOVE inout
if move < 1 or move > 9:
print("Wrong Input!!! Try Again")
continue
# Check if the box is not occupied already
if values[move-1] != ' ':
print("Place already filled. Try again!!")
continue
# Update game information
# Updating grid status
values[move-1] = cur_player
# Updating player positions
player_pos[cur_player].append(move)
# Function call for checking win
if check_win(player_pos, cur_player):
print_tic_tac_toe(values)
print("Player ", cur_player, " has won the game!!")
print("\n")
return cur_player
# Function call for checking draw game
if check_draw(player_pos):
print_tic_tac_toe(values)
print("Game Drawn")
print("\n")
return 'D'
# Switch player moves
if cur_player == 'X':
cur_player = 'O'
else:
cur_player = 'X'
if __name__ == "__main__":
print("Player 1")
player1 = input("Enter the name : ")
print("\n")
print("Player 2")
player2 = input("Enter the name : ")
print("\n")
# Stores the player who chooses X and O
cur_player = player1
# Stores the choice of players
player_choice = {'X' : "", 'O' : ""}
# Stores the options
options = ['X', 'O']
# Stores the scoreboard
score_board = {player1: 0, player2: 0}
print_scoreboard(score_board)
# Game Loop for a series of Tic Tac Toe
# The loop runs until the players quit
while True:
# Player choice Menu
print("Turn to choose for", cur_player)
print("Enter 1 for X")
print("Enter 2 for O")
print("Enter 3 to Quit")
# Try exception for CHOICE input
try:
choice = int(input())
except ValueError:
print("Wrong Input!!! Try Again\n")
continue
# Conditions for player choice
if choice == 1:
player_choice['X'] = cur_player
if cur_player == player1:
player_choice['O'] = player2
else:
player_choice['O'] = player1
elif choice == 2:
player_choice['O'] = cur_player
if cur_player == player1:
player_choice['X'] = player2
else:
player_choice['X'] = player1
elif choice == 3:
print("Final Scores")
print_scoreboard(score_board)
break
else:
print("Wrong Choice!!!! Try Again\n")
# Stores the winner in a single game of Tic Tac Toe
winner = single_game(options[choice-1])
# Edits the scoreboard according to the winner
if winner != 'D' :
player_won = player_choice[winner]
score_board[player_won] = score_board[player_won] + 1
print_scoreboard(score_board)
# Switch player who chooses X or O
if cur_player == player1:
cur_player = player2
else:
cur_player = player1