如何从一个链接生成解析的项目与来自同一项目列表中其他链接的其他解析项目

问题描述 投票:1回答:2

问题是我一直在从一个地方列表中进行迭代以刮取纬度经度和海拔。问题是,当我得到我所收回的内容时,我无法将其与我当前的df链接,因为我迭代的名称可能已被修改或跳过。

我已经设法获得了我所看到的名称,但由于它从外部解析了其他项目的链接,因此无法正常工作。

import scrapy
import pandas as pd
from ..items import latlonglocItem


df = pd.read_csv('wine_df_final.csv')
df = df[pd.notnull(df.real_place)]
real_place = list(set(df.real_place))


class latlonglocSpider(scrapy.Spider):


    name = 'latlonglocs'
    start_urls = []


    for place in real_place:
        baseurl =  place.replace(',', '').replace(' ', '+')
        cleaned_href = f'http://www.google.com/search?q={baseurl}+coordinates+latitude+longitude+distancesto'
        start_urls.append(cleaned_href)



    def parse(self, response):

        items = latlonglocItem()

        items['base_name'] = response.xpath('string(/html/head/title)').get().split(' coordinates')[0]
        for href in response.xpath('//*[@id="ires"]/ol/div/h3/a/@href').getall():
            if href.startswith('/url?q=https://www.distancesto'):
                yield response.follow(href, self.parse_distancesto)
            else:
                pass
        yield items

    def parse_distancesto(self, response):
        items = latlonglocItem()

        try:
            items['appellation'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[2]/p/strong)').get()
            items['latitude'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[3]/table/tbody/tr[1]/td)').get()
            items['longitude'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[3]/table/tbody/tr[2]/td)').get()
            items['elevation'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[3]/table/tbody/tr[10]/td)').get()
            yield items
        except Exception:
            pass
#output
 appellation      base_name       elevation    latitude    longitude
                  Chalone, USA
 Santa Cruz, USA                  56.81        35           9.23 

发生的事情是我解析我所寻找的东西然后它进入一个链接并解析其余的信息。然而,显然在我的数据框架上,我得到了我所寻找的与其他项目完全无关的名称,即使这样也很难找到匹配。我希望将信息传递给另一个函数,以便将所有项目一起生成。

python web-scraping scrapy
2个回答
0
投票

这可能有效。我将评论我正在做的事情以及你对我正在做的事情有所了解的一些代码。

import scrapy
import pandas as pd
from ..items import latlonglocItem


df = pd.read_csv('wine_df_final.csv')
df = df[pd.notnull(df.real_place)]
real_place = list(set(df.real_place))


class latlonglocSpider(scrapy.Spider): # latlonglocSpider is a child class of scrapy.Spider

    name = 'latlonglocs'
    start_urls = []

    for place in real_place:
        baseurl =  place.replace(',', '').replace(' ', '+')
        cleaned_href = f'http://www.google.com/search?q={baseurl}+coordinates+latitude+longitude+distancesto'
        start_urls.append(cleaned_href)

    def __init__(self): # Constructor for our class
        # Since we did our own constructor we need to call the parents constructor
        scrapy.Spider.__init__(self)
        self.base_name = None # Here is the base_name we can now use class wide

    def parse(self, response):

        items = latlonglocItem()

        items['base_name'] = response.xpath('string(/html/head/title)').get().split(' coordinates')[0]
        self.base_name = items['base_name'] # Lets store the base_name in the class
        for href in response.xpath('//*[@id="ires"]/ol/div/h3/a/@href').getall():
            if href.startswith('/url?q=https://www.distancesto'):
                yield response.follow(href, self.parse_distancesto)
            else:
                pass
        yield items

    def parse_distancesto(self, response):
        items = latlonglocItem()

        try:
            # If for some reason self.base_name is never assigned in
            # parse() then we want to use an empty string instead of the self.base_name

            # The following syntax means use self.base_name unless it is None or empty
            # in which case just use and empty string.
            base_name = self.base_name or "" # If for some reason

            items['appellation'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[2]/p/strong)').get()
            items['latitude'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[3]/table/tbody/tr[1]/td)').get()
            items['longitude'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[3]/table/tbody/tr[2]/td)').get()
            items['elevation'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[3]/table/tbody/tr[10]/td)').get()
            yield items
        except Exception:
            pass

0
投票
import scrapy
import pandas as pd
from ..items import latlonglocItem


df = pd.read_csv('wine_df_final.csv')
df = df[pd.notnull(df.real_place)]
real_place = list(set(df.real_place))


class latlonglocSpider(scrapy.Spider): # latlonglocSpider is a child class of scrapy.Spider

    name = 'latlonglocs'
    start_urls = []

    for place in real_place:
        baseurl =  place.replace(',', '').replace(' ', '+')
        cleaned_href = f'http://www.google.com/search?q={baseurl}+coordinates+latitude+longitude+distancesto'
        start_urls.append(cleaned_href)

    def __init__(self): # Constructor for our class
        # Since we did our own constructor we need to call the parents constructor
        scrapy.Spider.__init__(self)
        self.base_name = None # Here is the base_name we can now use class wide

    def parse(self, response):

        for href in response.xpath('//*[@id="ires"]/ol/div/h3/a/@href').getall():

            if href.startswith('/url?q=https://www.distancesto'):
                self.base_name = response.xpath('string(/html/head/title)').get().split(' coordinates')[0]

                yield response.follow(href, self.parse_distancesto)
            else:
                pass

    def parse_distancesto(self, response):
        items = latlonglocItem()

        try:
            # If for some reason self.base_name is never assigned in
            # parse() then we want to use an empty string instead of the self.base_name

            # The following syntax means use self.base_name unless it is None or empty
            # in which case just use and empty string.
            items['base_name'] = self.base_name or "" # If for some reason
            items['appellation'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[2]/p/strong)').get()
            items['latitude'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[3]/table/tbody/tr[1]/td)').get()
            items['longitude'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[3]/table/tbody/tr[2]/td)').get()
            items['elevation'] = response.xpath('string(/html/body/div[3]/div/div[2]/div[3]/div[3]/table/tbody/tr[10]/td)').get()
            yield items
        except Exception:
            pass

感谢Error - Syntactical Remorse。并发请求必须设置为1才能使其工作并将base_name放在循环中。

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