排除验证两个条件的记录

Question

select * from table_name
 where BaseDocEntry=15 and BaseDocType='PRRH' and ItemCode='TestStudy2'
   and WhseCode='01' and (currentdoctype<>'PUSH' and CurrentDocEntry<>15)

根据我上面写的查询，来自INS2的数据将被取出，不包括currentdoctype [PUSH]和CurrentDocEntry不是15的所有数据。我期望我的查询是，它必须排除数据，只有这个组合，即currentdoctype = PUSH和CurrentDocEntry = 15发生在同一行，然后排除该行。

你能解决这个问题吗？

Answer 1

用这个：

and not (currentdoctype='PUSH' and CurrentDocEntry=15)

Answer 2

由于您使用的是AND而不是OR，因此当currentdoctype与'PUSH'不同且CurrentDocEntry与15不同时，查询将被排除。

如果你想要currentdoctype = PUSH和CurrentDocEntry = 15，那就改为：

select * from ins2
where BaseDocEntry=15 and BaseDocType='PRRH' and ItemCode='TestStudy2'
and WhseCode='01' and (currentdoctype='PUSH' and CurrentDocEntry=15)

Answer 3

在NOT不起作用的某些情况下，您可以使用简单的case和where子句来解决它。这将仅排除currentdoctype ='PUSH'和CurrentDocEntry = 15的情况。

SELECT *,
CASE
WHEN currentdoctype ='PUSH' AND CurrentDocEntry = 15 THEN 'c1'
ELSE 'c2'
END AS com_con
FROM table_name
WHERE  BaseDocEntry=15 AND BaseDocType='PRRH' AND ItemCode='TestStudy2'
   AND WhseCode='01' AND com_con = 'c2';