基于其他两列的分组值获取均值列

问题描述 投票:0回答:1

我有一些学校资料:

data = {'name': ['school a', 'school b', 'school c', 'school d', 'school e', 'school f'], 
       'type': ['a', 'a', 'b', 'b', 'a', 'b'],
        'location': ['county a', 'county a', 'county b', 'county b', 'county b', 'county a'], 
        'avg_score': [9, 7, 5, 7, 6, 8]
       }

df = pd.DataFrame(data)


Out:
    name    type    location    avg_score
0   school a    a   county a    9
1   school b    a   county a    7
2   school c    b   county b    5
3   school d    b   county b    7
4   school e    a   county b    6
5   school f    b   county a    8

我想比较学校分数与每个位置的学校类型的平均值。

我可以使用groupby来做到这一点:df.groupby(['type', 'location']).mean().round(2)

Out: 

                avg_score
type location   
a   county a    8
    county b    6
b   county a    8
    county b    6

但是,我想获得一个额外的列,而不是分组表,该列的每个位置的该学校类型的平均值。

喜欢此:

        name       type        location      avg_score  compare_score
0   school a    a   county a    9   8
1   school b    a   county a    7   5
2   school c    b   county b    5   7
3   school d    b   county b    7   7
4   school e    a   county b    6   3
5   school f    b   county a    8   7

我发现了这个问题

Python Pandas average based on condition into new column

并尝试对我的问题应用一些可能的解决方案:

for atype, alocation in df.groupby('type'):
    df.loc[df.type == type, 'compare'] = (df.where(df['type' == atype]).where(df['location' == alocation]).mean()).avg_score.round(2)```

引发此错误:

---------------------------------------------------------------------------
KeyError                                  Traceback (most recent call last)
~/.local/share/virtualenvs/schule-jwiURUl3/lib/python3.6/site-packages/pandas/core/indexes/base.py in get_loc(self, key, method, tolerance)
   2656             try:
-> 2657                 return self._engine.get_loc(key)
   2658             except KeyError:

pandas/_libs/index.pyx in pandas._libs.index.IndexEngine.get_loc()

pandas/_libs/index.pyx in pandas._libs.index.IndexEngine.get_loc()

pandas/_libs/hashtable_class_helper.pxi in pandas._libs.hashtable.PyObjectHashTable.get_item()

pandas/_libs/hashtable_class_helper.pxi in pandas._libs.hashtable.PyObjectHashTable.get_item()

KeyError: False

During handling of the above exception, another exception occurred:

KeyError                                  Traceback (most recent call last)
<ipython-input-27-4b3cf2b7aaf6> in <module>
      1 for atype, alocation in df.groupby('type'):
----> 2     df.loc[df.type == type, 'compare'] = (df.where(df['type' == atype]).where(df['location' == alocation]).mean()).avg_score.round(2)

~/.local/share/virtualenvs/schule-jwiURUl3/lib/python3.6/site-packages/pandas/core/frame.py in __getitem__(self, key)
   2925             if self.columns.nlevels > 1:
   2926                 return self._getitem_multilevel(key)
-> 2927             indexer = self.columns.get_loc(key)
   2928             if is_integer(indexer):
   2929                 indexer = [indexer]

~/.local/share/virtualenvs/schule-jwiURUl3/lib/python3.6/site-packages/pandas/core/indexes/base.py in get_loc(self, key, method, tolerance)
   2657                 return self._engine.get_loc(key)
   2658             except KeyError:
-> 2659                 return self._engine.get_loc(self._maybe_cast_indexer(key))
   2660         indexer = self.get_indexer([key], method=method, tolerance=tolerance)
   2661         if indexer.ndim > 1 or indexer.size > 1:

pandas/_libs/index.pyx in pandas._libs.index.IndexEngine.get_loc()

pandas/_libs/index.pyx in pandas._libs.index.IndexEngine.get_loc()

pandas/_libs/hashtable_class_helper.pxi in pandas._libs.hashtable.PyObjectHashTable.get_item()

pandas/_libs/hashtable_class_helper.pxi in pandas._libs.hashtable.PyObjectHashTable.get_item()

KeyError: False

也许这根本不是一个好尝试。你有什么建议吗?任何提示都受到高度赞赏。

python-3.x pandas multiple-columns pandas-groupby mean
1个回答
0
投票
我认为您正在寻找transform

df['compare_score']=df.groupby(['type', 'location']).transform('mean').round(2) print(df) --------------- name type location avg_score compare_score 0 school a a county a 9 8 1 school b a county a 7 8 2 school c b county b 5 6 3 school d b county b 7 6 4 school e a county b 6 6 5 school f b county a 8 8

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