Snakemake歧义性

问题描述 投票:1回答:2

我有一个模棱两可的错误,我不知道为什么以及如何解决它。

定义通配符:

rule all:
    input:
        xls = expand("reports/{sample}.xlsx", sample = config["samples"]),
        runfolder_xls = expand("{runfolder}.xlsx", runfolder = config["runfolder"])

实际规则:

rule sample_report:
    input:
        vcf = "vcfs/{sample}.annotated.vcf",
        cov = "stats/{sample}.coverage.gz",
        mod_bed = "tmp/mod_ref_{sample}.bed",
        nirvana_g2t = "/mnt/storage/data/NGS/nirvana_genes2transcripts"
    output:
        "reports/{sample}.xlsx"
    params:
        get_nb_samples()
    log:
        "logs/{sample}.log"
    shell: """
        python /mnt/storage/home/kimy/projects/automate_CP/niles/NILES_create_sample_report.py -v {input.vcf} -c {input.cov} -r {input.mod_bed} -n {input.nirvana_g2t} -r {rule};
        exitcode=$? ;

        if [[ {params} > 1 ]]
        then
            python /mnt/storage/home/kimy/projects/automate_CP/niles/NILES_check_exitcode.py -e $exitcode -r {rule} -n {wildcards.sample}
        elif [[ {params} == 1 ]]
        then 
            python /mnt/storage/home/kimy/projects/automate_CP/niles/NILES_check_exitcode.py -e $exitcode -r sample_mode -n {wildcards.sample}
        else
            python /mnt/storage/home/kimy/projects/automate_CP/niles/NILES_check_exitcode.py -e 1 -r {rule} -n {wildcards.sample}
        fi
    """


rule runfolder_report:
    input:
        sample_sheet = "SampleSheet.csv"
    output:
        "{runfolder}.xlsx"
    log:
        "logs/{runfolder}.log"
    shell: """
        python /mnt/storage/home/kimy/projects/automate_CP/niles/NILES_create_runfolder_report.py -run {wildcards.runfolder} -s {input.sample_sheet} -r {rule} ;
        exitcode=$? ;
        python /mnt/storage/home/kimy/projects/automate_CP/niles/NILES_check_exitcode.py -e $exitcode -r {rule} -n {wildcards.runfolder}
    """

配置文件:

runfolder: "CP0340"

samples: ['C014044p', 'C130157', 'C014040p', 'C014054b-1', 'C051198-A', 'C014042p', 'C052007W-C', 'C051198-B', 'C014038p', 'C052004-B', 'C051198-C', 'C052004-C', 'C052003-B', 'C052003-A', 'C052004-A', 'C052002-C', 'C052005-C', 'C052002-A', 'C130157N', 'C052006-B', 'C014063pW', 'C014054b-2', 'C052002-B', 'C052006-C', 'C052007W-B', 'C052003-C', 'C014064bW', 'C052005-B', 'C052006-A', 'C052005-A']

错误:

$ snakemake -n -s ../niles/Snakefile --configfile logs/CP0340_config.yaml
Building DAG of jobs...
AmbiguousRuleException:
Rules runfolder_report and sample_report are ambiguous for the file reports/C014044p.xlsx.
Consider starting rule output with a unique prefix, constrain your wildcards, or use the ruleorder directive.
Wildcards:
        runfolder_report: runfolder=reports/C014044p
        sample_report: sample=C014044p
Expected input files:
        runfolder_report: SampleSheet.csv
        sample_report: vcfs/C014044p.annotated.vcf stats/C014044p.coverage.gz tmp/mod_ref_C014044p.bed /mnt/storage/data/NGS/nirvana_genes2transcriptsExpected output files:
        runfolder_report: reports/C014044p.xlsx
        sample_report: reports/C014044p.xlsx

如果我正确理解了Snakemake,则在我的所有规则中定义了规则中的通配符,所以我不明白为什么runfolder_report规则试图将report / C014044p.xlsx用作输出+输出如何具有示例名称而不是运行文件夹名称(在配置文件中定义)。

python bioinformatics snakemake
2个回答
0
投票

确定,这是我的解决方法:

rule runfolder_report:
    input:
        "SampleSheet.csv"
    output:
        expand("{runfolder}.xlsx", runfolder = config["runfolder"])
    params:
        config["runfolder"]
    log:
        expand("logs/{runfolder}.log", runfolder = config["runfolder"])
    shell: """
        set +e ;

        python /mnt/storage/home/kimy/projects/automate_CP/niles/NILES_create_runfolder_report.py -run {params} -s {input} -r {rule} ;
        exitcode=$? ;
        python /mnt/storage/home/kimy/projects/automate_CP/niles/NILES_check_exitcode.py -e $exitcode -r {rule} -n {params}
    """

但是我仍然不明白为什么会有错误,并且我知道它以前可以工作。


0
投票

如错误消息所提示,您可以为每个规则的输出分配一个不同的前缀。因此,如果您将规则{runfolder}.xlsx"runfolder/{runfolder}.xlsx"中的all替换为runfolder_report,则您的原始代码将可以使用。或者,通过在规则all之前添加以下内容来约束通配符(我的首选解决方案):

wildcard_constraints:
    sample= '|'.join([re.escape(x) for x in config["samples"]]),
    runfolder= re.escape(config["runfolder"]),

这样做的原因是,snakemake使用正则表达式匹配输入和输出字符串(其完成方式的精细细节,我必须承认,逃避了我...)

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