一周特定小时部分的数据总和 - MS SQL查询

问题描述 投票:1回答:1

为了查找一周的数据总和(在我的情况下为CallsAnswered),但在下午6点到12点之间找到特定的小时数,我在下面设置了一个查询,但它在我的样本数据中跳过了一天的数据。你可以验证我的查询并帮助我找到我失踪的地方吗?

创建查询:

Create Table tblSingleBox (ScanDate DateTime, SkillTargetID Varchar(10), CallsAnswered int)

插入查询

Insert into tblSingleBox 
Values ('2018-02-18 19:17:01', '10888', 32),
('2018-02-18 23:59:59', '10888', 01),
('2018-02-19 00:10:01', '10888', 15),
('2018-02-19 17:59:59', '10889', 12),
('2018-02-19 20:59:59', '10889', 90),
('2018-02-25 21:59:59', '10889', 40)

查询:

SELECT convert(varchar(10),ScanDate,101)ScanDate,SkillTargetID, SUM(CallsAnswered)CallsAnswered
FROM    tblSingleBox (nolock)
WHERE    DATEPART(Hour, scandate) between 18 and 24
    and (scandate between '2018-02-18' and '2018-02-25')
GROUP BY    convert(varchar(10),ScanDate,101) ,SkillTargetID
order by convert(varchar(10),ScanDate,101)

预期产出:

ScanDate    SkillTargetID   CallsAnswered
18-02-2018  10888   33
18-02-2018  10889   11
19-02-2018  10889   90
25-02-2018  10889   40

我得到的实际产量:

ScanDate    SkillTargetID   CallsAnswered
02/18/2018  10888   33
02/18/2018  10889   11
02/19/2018  10889   90
sql-server sql-server-2014 datepart
1个回答
2
投票

scandate有时间,2018-02-25 21:59:59大于2018-02-25(与DATETIME相比,被视为2018-02-25 00:00:00)。

因此,将scandate投射到DATE(截止时间)或改变

scandate between '2018-02-18' and '2018-02-25'

scandate >= '2018-02-18' and scandate < '2018-02-26'
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