在 GitHub macos-14 runner 上使用 cibuildwheel 和 scikit-build-core 时，CMAKE_SYSTEM_PROCESSOR 的值不正确

Question

下面是重现该问题的演示文件。我预计

CMAKE_SYSTEM_PROCESSOR

的值应该是

arm64

。然而，它是

x86_64

。请参阅 Buildwheels 部分中的第 1233 行，该行对应于

message("CMAKE_SYSTEM_PROCESSOR: ${CMAKE_SYSTEM_PROCESSOR}")

文件中的命令

CMakeLists.txt

main.cpp

#include <iostream>

int main() {
    std::cout << "hello\n";
}

CMakeLists.txt

cmake_minimum_required(VERSION 3.25)
project(hello)
set(CMAKE_CXX_STANDARD 17)
message("CMAKE_SYSTEM_PROCESSOR: ${CMAKE_SYSTEM_PROCESSOR}")
add_executable(hello main.cpp)

build-wheel.yml

name: build-wheels

on:
  push:

jobs:
  build_wheels:
    name: Build wheel
    runs-on: macos-14

    steps:
      - uses: actions/checkout@v3

      - name: Select Xcode
        run: sudo xcode-select -s /Applications/Xcode_15.4.app
      
      - name: Install Homebrew and packages
        run: |
          /bin/bash -c "$(curl -fsSL https://raw.githubusercontent.com/Homebrew/install/HEAD/install.sh)"
          brew update
          brew install ninja

      - name: Build wheels
        uses: pypa/[email protected]
        env:
          CIBW_BUILD: cp38-macosx_arm64
          CIBW_BUILD_VERBOSITY: 2
          CIBW_ENVIRONMENT_MACOS: >
            CC=gcc-14
            CXX=g++-14
            MACOSX_DEPLOYMENT_TARGET=13.0

pyproject.toml

[build-system]
requires = ["scikit-build-core>=0.9.0"]
build-backend = "scikit_build_core.build"

[project]
name = "hello"
version = "0.0.1dev0"

requires-python = ">=3.8"
dependencies = []

classifiers = [
  "License :: OSI Approved :: GNU General Public License v3 or later (GPLv3+)",
  "Programming Language :: Python :: 3 :: Only",
  "Programming Language :: Python :: 3.8",
  "Programming Language :: Python :: 3.9",
  "Programming Language :: Python :: 3.10",
  "Programming Language :: Python :: 3.11",
  "Programming Language :: Python :: 3.12",
]


[tool.scikit-build]
wheel.expand-macos-universal-tags = true
cmake.version = ">=3.25"
cmake.build-type = "Release"
cmake.verbose = true
logging.level = "INFO"

[tool.cibuildwheel]
build = "*"
skip = "cp3{6,7}-*"

如果我直接使用下面的工作流程文件构建程序。我得到了

CMAKE_SYSTEM_PROCESSOR

的正确值，即

arm64

。请参阅Build部分中的第29行。

build.yml

name: build

on:
  push:

jobs:
  build:
    name: Build
    runs-on: macos-14

    steps:
      - uses: actions/checkout@v3

      - name: Select Xcode
        run: sudo xcode-select -s /Applications/Xcode_15.4.app
      
      - name: Install Homebrew and packages
        run: |
          /bin/bash -c "$(curl -fsSL https://raw.githubusercontent.com/Homebrew/install/HEAD/install.sh)"
          brew update
          brew install ninja

      - name: "Build"
        run: |
          rm -rf build && mkdir build && cd build
          cmake -DCMAKE_C_COMPILER=gcc-14 \
                -DCMAKE_CXX_COMPILER=g++-14 \
                -DCMAKE_BUILD_TYPE=Release \
                -GNinja .. 
          ninja

Answer 1

找到解决方案。这是由于 python 3.8 https://cibuildwheel.pypa.io/en/stable/faq/#macos-building-cpython-38-wheels-on-arm64