内核调用产生错误“错误:无法配置主机函数调用”。调用有什么问题?

问题描述 投票:-2回答:1

使用nvcc -c mag_cuda.cu编译以下代码时:

//Standard Libraries
#include <iostream>
#include <math.h>
#include <vector>

//Project Specific Header
#include "mag.hpp"

 __global__
  void indv_B_components(int *self_coords, int pole_coords[][3], double *indv_B[][3], int No_poles, int counter_1)
  {
    some code......
  }

  //----------------------------------------------------------
  //------- Function to Calculate B Field at Each Pole -------
  //----------------------------------------------------------
  void calc_indv_B()
  {
    //declare namepspace for internal variables
    using namespace mag::internal;

    int *ppole_coords = &pole_coords[0][0];
    double *pindv_B;
    int self_coords[3];

    int num_threads_in_block = 256;
    int num_blocks = 32*2;

    cudaMallocManaged(&pindv_B, No_poles*3*sizeof(int));  


    //first loop to go over all poles
    for(int counter_1 = 0; counter_1 < No_poles; counter_1++)
      {
      //store coords of the current pole
      self_coords[0] = pole_coords[counter_1][0];
      self_coords[1] = pole_coords[counter_1][1];
      self_coords[2] = pole_coords[counter_1][2];


      indv_B_components<<<num_blocks, num_threads_in_block>>>(self_coords, ppole_coords,  pindv_B, No_poles, counter_1); 



      cudaDeviceSynchronize();
      }

    cudaFree(pindv_B);

    //return from function
    return;
  }

返回以下错误:

错误:无法配置主机函数调用

哪指线

indv_B_components<<<num_blocks, num_threads_in_block>>>(self_coords, ppole_coords,  pindv_B, No_poles, counter_1); 

由于所有参数都已定义,并且主机设备调用的内核声明为__global__,因此我不知道是什么导致这种情况。

头文件mag.hpp是:

//make sure MAG_H_ module hasnt been defined multiple times
#ifndef MAG_H_
#define MAG_H_

//standard libraries
#include <iostream>
#include <math.h>
#include <vector>


//Namespace for module
namespace mag
{


  //define functions
  ...


  void indv_B_components(int *self_coords, int *pole_coords, double *indv_B, int No_poles, int counter_1);

  void calc_indv_B();

  ...
}
#endif //MAG_H_

有帮助吗?

c++ compiler-errors cuda
1个回答
4
投票

发生此错误的一种情况是,如果在调用内核时没有__global__说明符的内核函数只是“声明”,例如:

void kernel();

void f()
{
    kernel<<<1, 1>>>();
}

__global__
void kernel()
{
}

live demo here

内核函数的声明必须包含__global__说明符:

__global__ void kernel();

否则声明不会声明内核函数,而只是一个普通的主机函数,这就是编译器然后抱怨的原因,因为只有内核函数可以在GPU上启动...

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