如何在Python中将第n个数组的数组元素相乘？

Question

我正在尝试在 Python 中创建从第 n 个数组创建数组的方法。我看过 Numpy 但该方法似乎不适合我的要求。 以下是我的 JavaScript 代码。 numArr = [[1],[12],[22],[31,32,33],[41,42]] ，结果将是 [1,12,22,31,41],[1,12,22,31,42],[1,12,22,32,41],[1,12,22,32,42],[1 ,12,22,33,41],[1,12,22,33,42]

for (var i = 0; i < numArr.length; i++) {
    tempNumArr = new Array(totalNumArr.length * numArr[i].length);
    for (var j = 0; j < totalNumArr.length; j++) {
      for (var k = 0; k < numArr[i].length; k++) {
        tempNumArr[j * numArr[i].length + k] = new Array();
        if (i !== 0)
          tempNumArr[j * numArr[i].length + k] = totalNumArr[j].slice();

        tempNumArr[j * numArr[i].length + k].push(numArr[i][k]);
      }
    }
    totalNumArr = tempNumArr;
  }

Answer 1

所以基本上我们需要连接 N 个数组并返回连接数组 N 次。

arr = np.concatenate(numArr)
arr = arr * len(numArr)

Answer 2

你要找的是数组的乘积

import itertools

ls = [[1],[12],[22],[31,32,33],[41,42]]

print([p for p in itertools.product(*ls)])