在数据库中搜索文本和int，返回错误 多部分标识符...不能被绑定。

问题描述 投票：0回答：1

我试着修改了现有的搜索所有表格的脚本，我发现(在这个答案中 从2009年开始）加入INT选项，但我得到一个错误。

Msg 4104, Level 16, State 1, Line 1 The multi-part identifier "dbo.ADACS_MAPS" could not be bound.

当我运行数据库中的每一列时，都会出现这样的错误。

ALTER PROC [dbo].[SearchAllTables]
(
    @SearchStr nvarchar(100),
    @SearchInt int = 0
)
AS
BEGIN

-- Copyright © 2002 Narayana Vyas Kondreddi. All rights reserved.
-- Purpose: To search all columns of all tables for a given search string
-- Written by: Narayana Vyas Kondreddi
-- Site: http://vyaskn.tripod.com
-- Tested on: SQL Server 7.0 and SQL Server 2000
-- Date modified: 28th July 2002 22:50 GMT

DECLARE @Results TABLE(ColumnName nvarchar(370), ColumnValue nvarchar(3630))

SET NOCOUNT ON

DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110)
SET  @TableName = ''
SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')

WHILE @TableName IS NOT NULL
BEGIN
    SET @ColumnName = ''
    SET @TableName = 
    (
        SELECT MIN(QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME))
        FROM    INFORMATION_SCHEMA.TABLES
        WHERE       TABLE_TYPE = 'BASE TABLE'
            AND QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME) > @TableName
            AND OBJECTPROPERTY(
                    OBJECT_ID(
                        QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME)
                         ), 'IsMSShipped'
                           ) = 0
    )

    WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)
    BEGIN
        SET @ColumnName =
        (
            SELECT MIN(QUOTENAME(COLUMN_NAME))
            FROM    INFORMATION_SCHEMA.COLUMNS
            WHERE       TABLE_SCHEMA    = PARSENAME(@TableName, 2)
                AND TABLE_NAME  = PARSENAME(@TableName, 1)
                AND DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar', 'int')
                AND QUOTENAME(COLUMN_NAME) > @ColumnName
        )

        IF @ColumnName IS NOT NULL
        BEGIN
            INSERT INTO @Results
            EXEC
            (
                'if exists (SELECT name FROM SYSOBJECTS WHERE xtype = ''U'' and name like trim('']'' from SUBSTRING(' + @TableName + ' , 8, 100))) BEGIN '
               +'SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630) 
                FROM ' + @TableName + ' (NOLOCK) ' +
                ' WHERE ' + @ColumnName + ' = ' + @SearchInt
               +' END
               ELSE
                BEGIN '
               +
                'SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630) 
                FROM ' + @TableName + ' (NOLOCK) ' +
                ' WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
                +' END'
            )
        END
    END 
END

SELECT ColumnName, ColumnValue FROM @Results
END

谁能指出我做错了什么，因为这（我不羞于承认）超出了我的知识范围。

你应该可以在任何DB上运行这个，所以我没有包括演示数据。

编辑1:

我唯一修改的部分是：

  1. 增加了param
  2. 将最后的选择从。
EXEC
   (
      'SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630) 
      FROM ' + @TableName + ' (NOLOCK) ' +
      ' WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
   )

改成现在的样子

编辑2:

找到了一个解决方案 此处 这很好用，但我会在我的脚本上下功夫，看看为什么它不工作。

感谢前两位评论者的帮助，我会按照建议使用select更仔细地查看那段代码。

sql sql-server database search
1个回答
0
投票

当我在调试开发动态代码时，我倾向于使用print语句来查看我的代码哪里出了问题。我把过程拆开，然后打印包含动态sql的变量。你也可以使用调试器。

发生的情况是，在你的动态代码中，你正在搜索一个不存在的列。这是因为你缺少了额外的引号来转换为字符串。下面是当我在北风数据库中使用你的过程并搜索'cat'时，打印的第一段动态代码。

if exists (SELECT name 
            FROM SYSOBJECTS 
            WHERE xtype = 'U' 
-- SQL server sees [dbo].[Categories] as a non existing column
            and name like trim(']' from SUBSTRING([dbo].[Categories] , 8, 100))) 
            BEGIN 
            SELECT '[dbo].[Categories].[CategoryID]', LEFT([CategoryID], 3630) 
                FROM [dbo].[Categories] (NOLOCK)  WHERE 
                [CategoryID] = 1 END
               ELSE
                BEGIN SELECT '[dbo].[Categories].[CategoryID]', LEFT([CategoryID], 3630) 
                FROM [dbo].[Categories] (NOLOCK)  WHERE [CategoryID] LIKE '%cat%' END

下面是对你的代码进行的两处修改，使其工作。额外的引号和一个额外的变量，由于你要查找的表的名称列中没有模式，所以剥离了模式。

ALTER PROC [dbo].[SearchAllTables]
(
    @SearchStr nvarchar(100),
    @SearchInt int = 0
)
AS
BEGIN

-- Copyright © 2002 Narayana Vyas Kondreddi. All rights reserved.
-- Purpose: To search all columns of all tables for a given search string
-- Written by: Narayana Vyas Kondreddi
-- Site: http://vyaskn.tripod.com
-- Tested on: SQL Server 7.0 and SQL Server 2000
-- Date modified: 28th July 2002 22:50 GMT

DECLARE @Results TABLE(ColumnName nvarchar(370), ColumnValue nvarchar(3630))

SET NOCOUNT ON

DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110), @TableNoSchema nvarchar(256)
SET  @TableName = ''
SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')

WHILE @TableName IS NOT NULL
BEGIN
    SET @ColumnName = ''
    SET @TableName = 
    (
        SELECT MIN(QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME))
        FROM    INFORMATION_SCHEMA.TABLES
        WHERE       TABLE_TYPE = 'BASE TABLE'
            AND QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME) > @TableName
            AND OBJECTPROPERTY(
                    OBJECT_ID(
                        QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME)
                         ), 'IsMSShipped'
                           ) = 0
    )
    -- Since the table used below in the dynamic SQL does not have a prepended schema is strip it here
    SET @TableNoSchema = SUBSTRING(@TableName, CHARINDEX('.',@TableName) + 2, LEN(@TableName) - CHARINDEX('.',@TableName) -2 )

    WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)
    BEGIN
        SET @ColumnName =
        (
            SELECT MIN(QUOTENAME(COLUMN_NAME))
            FROM    INFORMATION_SCHEMA.COLUMNS
            WHERE       TABLE_SCHEMA    = PARSENAME(@TableName, 2)
                AND TABLE_NAME  = PARSENAME(@TableName, 1)
                AND DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar', 'int')
                AND QUOTENAME(COLUMN_NAME) > @ColumnName
        )

        IF @ColumnName IS NOT NULL
        BEGIN
            INSERT INTO @Results
            EXEC -- only added extra quotes so SQL server sees a string instead of a column
            (
                'if exists (SELECT name FROM SYSOBJECTS WHERE xtype = ''U'' and name like trim('']'' from SUBSTRING(''' + @TableNoSchema + ''' , 8, 100))) BEGIN '
               +'SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630) 
                FROM ' + @TableName + ' (NOLOCK) ' +
                ' WHERE ' + @ColumnName + ' = ' + @SearchInt
               +' END
               ELSE
                BEGIN '
               +
                'SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630) 
                FROM ' + @TableName + ' (NOLOCK) ' +
                ' WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
                +' END'
            )
        END
    END 
END

SELECT ColumnName, ColumnValue FROM @Results
END
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