我想在这个对象中总计每个杯子的匹配和参与者的总数：
{
"Cup_1": {
"bronze": {
"matches": 3,
"participants": 289
},
"silver": {
"matches": 20,
"participants": 1874
},
"gold": {
"matches": 35,
"participants": 3227
},
"platinum": {
"matches": 3,
"participants": 294
},
"diamond": {
"matches": 5,
"participants": 482
},
"ace": {
"matches": 6,
"participants": 574
}
},
"Cup_2": {
"bronze": {
"matches": 17,
"participants": 1609
},
"silver": {
"matches": 46,
"participants": 4408
},
"gold": {
"matches": 157,
"participants": 14391
},
"platinum": {
"matches": 0,
"participants": 0
},
"diamond": {
"matches": 5,
"participants": 469
},
"ace": {
"matches": 10,
"participants": 959
}
},
"Cup_3": {
"bronze": {
"matches": 35,
"participants": 3358
},
"silver": {
"matches": 96,
"participants": 9069
},
"gold": {
"matches": 313,
"participants": 29527
},
"platinum": {
"matches": 10,
"participants": 960
},
"diamond": {
"matches": 16,
"participants": 1538
},
"ace": {
"matches": 45,
"participants": 4280
}
},
"Cup_4": {
"bronze": {
"matches": 2,
"participants": 187
},
"silver": {
"matches": 8,
"participants": 742
},
"gold": {
"matches": 37,
"participants": 3416
},
"platinum": {
"matches": 0,
"participants": 0
},
"diamond": {
"matches": 2,
"participants": 196
},
"ace": {
"matches": 3,
"participants": 290
}
},
"Cup_5": {
"bronze": {
"matches": 89,
"participants": 1638
}
}
}
当对象里面有另一个对象时，我不知道如何对属性求和（对不起，我还没有学到）;
我想要一个新的对象，每个杯子的总比赛结果和参赛者总数。还有除cup_5之外的所有杯子的每个类别的总匹配和参与者，因为它只有一个类别。
就像是：
Cup_1总比赛：72
Cup_1总参与人数：6740
铜牌总数（所有杯子）：57;
青铜参与者总数（所有杯子）：5443
示例新对象的结果：
var cups_result = {
"Total_Cup_1": {
matches: 72,
participants: 6740,
},
"Total_Bronze": {
matches: 57,
participants: 5443,
},
}
我读到这个对象属性的总和可以用.map完成，但我不知道如何正确使用map与对象。
如果有人能帮助我，我将不胜感激！
我仍然会将每杯的总数与每枚奖牌的总数分开，也可以加上一个总数（因为我们在这里）：
const data = {"Cup_1": {"bronze": {"matches": 3,"participants": 289},"silver": {"matches": 20,"participants": 1874},"gold": {"matches": 35,"participants": 3227},"platinum": {"matches": 3,"participants": 294},"diamond": {"matches": 5,"participants": 482},"ace": {"matches": 6,"participants": 574}},"Cup_2": {"bronze": {"matches": 17,"participants": 1609},"silver": {"matches": 46,"participants": 4408},"gold": {"matches": 157,"participants": 14391},"platinum": {"matches": 0,"participants": 0},"diamond": {"matches": 5,"participants": 469},"ace": {"matches": 10,"participants": 959}},"Cup_3": {"bronze": {"matches": 35,"participants": 3358},"silver": {"matches": 96,"participants": 9069},"gold": {"matches": 313,"participants": 29527},"platinum": {"matches": 10,"participants": 960},"diamond": {"matches": 16,"participants": 1538},"ace": {"matches": 45,"participants": 4280}},"Cup_4": {"bronze": {"matches": 2,"participants": 187},"silver": {"matches": 8,"participants": 742},"gold": {"matches": 37,"participants": 3416},"platinum": {"matches": 0,"participants": 0},"diamond": {"matches": 2,"participants": 196},"ace": {"matches": 3,"participants": 290}},"Cup_5": {"bronze": {"matches": 89,"participants": 1638}}}
const cupTotals = {},
medalTotals = {},
grandTotal = { matches: 0, participants: 0 };
for (const cup in data) {
cupTotals[cup] = { matches: 0, participants: 0 };
for (let medal in data[cup]) {
const {matches, participants} = data[cup][medal];
if (cup === "Cup_5" && medal === "bronze") medal = "junior";
cupTotals[cup].matches += matches;
cupTotals[cup].participants += participants;
if (!medalTotals[medal]) medalTotals[medal] = { matches: 0, participants: 0 };
medalTotals[medal].matches += matches;
medalTotals[medal].participants += participants;
grandTotal.matches += matches;
grandTotal.participants += participants;
}
}
const results = { cupTotals, medalTotals, grandTotal };
console.log(results);嵌套for循环将有助于从cups var中获取匹配和参与者字段。
for (var c in cups) {
for ( let medal in cups[c] ) {
console.log(cups[c][medal]["matches"], cups[c][medal]["participants"]);
}
}
您可以使用Object.keys，Object.values和destructuring - 下面返回每个杯子的摘要：
const cup_data = {
"Cup_1": {
"bronze": {
"matches": 3,
"participants": 289
},
"silver": {
"matches": 20,
"participants": 1874
},
"gold": {
"matches": 35,
"participants": 3227
},
"platinum": {
"matches": 3,
"participants": 294
},
"diamond": {
"matches": 5,
"participants": 482
},
"ace": {
"matches": 6,
"participants": 574
}
},
"Cup_2": {
"bronze": {
"matches": 17,
"participants": 1609
},
"silver": {
"matches": 46,
"participants": 4408
},
"gold": {
"matches": 157,
"participants": 14391
},
"platinum": {
"matches": 0,
"participants": 0
},
"diamond": {
"matches": 5,
"participants": 469
},
"ace": {
"matches": 10,
"participants": 959
}
},
"Cup_3": {
"bronze": {
"matches": 35,
"participants": 3358
},
"silver": {
"matches": 96,
"participants": 9069
},
"gold": {
"matches": 313,
"participants": 29527
},
"platinum": {
"matches": 10,
"participants": 960
},
"diamond": {
"matches": 16,
"participants": 1538
},
"ace": {
"matches": 45,
"participants": 4280
}
},
"Cup_4": {
"bronze": {
"matches": 2,
"participants": 187
},
"silver": {
"matches": 8,
"participants": 742
},
"gold": {
"matches": 37,
"participants": 3416
},
"platinum": {
"matches": 0,
"participants": 0
},
"diamond": {
"matches": 2,
"participants": 196
},
"ace": {
"matches": 3,
"participants": 290
}
},
"Cup_5": {
"bronze": {
"matches": 89,
"participants": 1638
}
}
};
let cup_results = {};
Object.keys(cup_data).forEach(key => {
let newCupKey = "Total_" + key;
cup_results[newCupKey] = {};
cup_results[newCupKey].matches = Object.values(cup_data[key]).reduce((acc, {
matches
}) => acc + matches, 0);
cup_results[newCupKey].participants = Object.values(cup_data[key]).reduce((acc, {
participants
}) => acc + participants, 0);
});
console.log(cup_results);为结果创建一个空对象。然后使用forEach()循环遍历所有杯子。并将结果存储在空对象中。
let data = {
"Cup_1": {
"bronze": {
"matches": 3,
"participants": 289
},
"silver": {
"matches": 20,
"participants": 1874
},
"gold": {
"matches": 35,
"participants": 3227
},
"platinum": {
"matches": 3,
"participants": 294
},
"diamond": {
"matches": 5,
"participants": 482
},
"ace": {
"matches": 6,
"participants": 574
}
},
"Cup_2": {
"bronze": {
"matches": 17,
"participants": 1609
},
"silver": {
"matches": 46,
"participants": 4408
},
"gold": {
"matches": 157,
"participants": 14391
},
"platinum": {
"matches": 0,
"participants": 0
},
"diamond": {
"matches": 5,
"participants": 469
},
"ace": {
"matches": 10,
"participants": 959
}
},
"Cup_3": {
"bronze": {
"matches": 35,
"participants": 3358
},
"silver": {
"matches": 96,
"participants": 9069
},
"gold": {
"matches": 313,
"participants": 29527
},
"platinum": {
"matches": 10,
"participants": 960
},
"diamond": {
"matches": 16,
"participants": 1538
},
"ace": {
"matches": 45,
"participants": 4280
}
},
"Cup_4": {
"bronze": {
"matches": 2,
"participants": 187
},
"silver": {
"matches": 8,
"participants": 742
},
"gold": {
"matches": 37,
"participants": 3416
},
"platinum": {
"matches": 0,
"participants": 0
},
"diamond": {
"matches": 2,
"participants": 196
},
"ace": {
"matches": 3,
"participants": 290
}
},
"Cup_5": {
"bronze": {
"matches": 89,
"participants": 1638
}
}
}
function sumOfCup(obj,cupNos,cuptypes){
let result = {};
Object.keys(obj).forEach(a => {
Object.keys(obj[a]).forEach(x => {
if(result[`Total_${x}`]){
result[`Total_${x}`].matches += obj[a][x].matches;
result[`Total_${x}`].participants += obj[a][x].participants;
}
else result[`Total_${x}`] = {...obj[a][x]};
})
result[`Total_${a}`] = Object.values(obj[a]).reduce((ac,a)=>{
ac.matches += a.matches
ac.participants += a.participants;
return ac;
},{matches:0,participants:0})
})
return result
}
console.log(data);
console.log(sumOfCup(data))当然，你可以制作一个单一的功能，可以完成你需要的一切，但如果你把它分解成更小的想法，它可能会更容易理解和维护。
例如，您可以创建一个只接受一个对象并返回matches和participants之和的函数。这将是简短的，可读的，最重要的是，可重用：
function sumObj(obj){
// returns the sum of matches and participant propertes of all obj's values
return Object.values(obj).reduce((sums, o) => {
sums.matches += o.matches
sums.participants += o.participants
return sums
}, {matches: 0, participants: 0})
}
现在，您可以通过各种方式使用和重用此功能。例如，要获取较大对象的所有主要类别，只需对值进行reduce，并为每个obj设置一个新键：
let o = {"Cup_1": {"bronze": {"matches": 3,"participants": 289},"silver": {"matches": 20,"participants": 1874},"gold": {"matches": 35,"participants": 3227},"platinum": {"matches": 3,"participants": 294},"diamond": {"matches": 5,"participants": 482},"ace": {"matches": 6,"participants": 574}},"Cup_2": {"bronze": {"matches": 17,"participants": 1609},"silver": {"matches": 46,"participants": 4408},"gold": {"matches": 157,"participants": 14391},"platinum": {"matches": 0,"participants": 0},"diamond": {"matches": 5,"participants": 469},"ace": {"matches": 10,"participants": 959}},"Cup_3": {"bronze": {"matches": 35,"participants": 3358},"silver": {"matches": 96,"participants": 9069},"gold": {"matches": 313,"participants": 29527},"platinum": {"matches": 10,"participants": 960},"diamond": {"matches": 16,"participants": 1538},"ace": {"matches": 45,"participants": 4280}},"Cup_4": {"bronze": {"matches": 2,"participants": 187},"silver": {"matches": 8,"participants": 742},"gold": {"matches": 37,"participants": 3416},"platinum": {"matches": 0,"participants": 0},"diamond": {"matches": 2,"participants": 196},"ace": {"matches": 3,"participants": 290}},"Cup_5": {"bronze": {"matches": 89,"participants": 1638}}}
/*
* Base function. Sum an object's matches & participants
*/
function sumObj(obj){
return Object.values(obj).reduce((sums, o) => {
sums.matches += o.matches
sums.participants += o.participants
return sums
}, {matches: 0, participants: 0})
}
let sums = Object.entries(o).reduce((totals, [key, val]) => {
totals[key] = sumObj(val) // call the sum function for each value
return totals
}, {})
console.log(sums)
/*
* Pass sums back into the same function to get a grand total:
*/
console.log("grand total: ", sumObj(sums))
/*
* To sum only a subset filter the obj entries first:
* Without Cup_5
*/
let minus_5 = Object.entries(o)
.filter(([k, v ]) => k != 'Cup_5') // filter first
.reduce((totals, [key, val]) => {
totals[key] = sumObj(val) // call the sum function for each value
return totals
}, {})
console.log("all but Cup_5", minus_5)
/*
* To get only a subcategory, use map and make a new
* array and pass it to the function:
* Only bronze:
*/
let bronze = Object.values(o).map(item => item.bronze) // get only bronze
console.log("Bronze", sumObj(bronze))正如您应该看到的，这非常灵活，可以让您使用相同的核心功能创建许多不同的报告。
我认为下面的功能应该是你的问题的通用解决方案。
const data = {"Cup_1": {"bronze": {"matches": 3,"participants": 289},"silver": {"matches": 20,"participants": 1874},"gold": {"matches": 35,"participants": 3227},"platinum": {"matches": 3,"participants": 294},"diamond": {"matches": 5,"participants": 482},"ace": {"matches": 6,"participants": 574}},"Cup_2": {"bronze": {"matches": 17,"participants": 1609},"silver": {"matches": 46,"participants": 4408},"gold": {"matches": 157,"participants": 14391},"platinum": {"matches": 0,"participants": 0},"diamond": {"matches": 5,"participants": 469},"ace": {"matches": 10,"participants": 959}},"Cup_3": {"bronze": {"matches": 35,"participants": 3358},"silver": {"matches": 96,"participants": 9069},"gold": {"matches": 313,"participants": 29527},"platinum": {"matches": 10,"participants": 960},"diamond": {"matches": 16,"participants": 1538},"ace": {"matches": 45,"participants": 4280}},"Cup_4": {"bronze": {"matches": 2,"participants": 187},"silver": {"matches": 8,"participants": 742},"gold": {"matches": 37,"participants": 3416},"platinum": {"matches": 0,"participants": 0},"diamond": {"matches": 2,"participants": 196},"ace": {"matches": 3,"participants": 290}},"Cup_5": {"bronze": {"matches": 89,"participants": 1638}}};
function getCumlativeData(data) {
return Object.keys(data).reduce((cumData, cup)=>{
let cupCumlative = {matches: 0, participants:0};
Object.keys(data[cup]).forEach(med => {
cumData[`Total_${med}`] = cumData[`Total_${med}`] || {matches: 0, participants:0};
cumData[`Total_${med}`] = {
matches: cumData[`Total_${med}`].matches + data[cup][med].matches,
participants: cumData[`Total_${med}`].participants + data[cup][med].participants,
};
cupCumlative = {
matches: cupCumlative.matches + data[cup][med].matches,
participants: cupCumlative.participants + data[cup][med].participants
};
});
return {...cumData, [`Total_${cup}`]: cupCumlative};
},{});
}
console.log(getCumlativeData(data));