我想编写一个 RISC-V 汇编代码，从给定数组中删除零并存储在相同的确切内存地址中

Question

我想从给定数组中删除零个数字，该数组包含以最后一个元素

-1

结尾的数字序列。 例如：

arr2: .word 0 0 2 0 0 -1 ====> arr: .word 2 -1
arr: .word 0 3 0 0 3 0 3 0 -1 ====> arr: .word 3 3 3 -1

我尝试编写这段代码：

.data
arr: .word 0 0 2 0 0 -1
.macro print_int (%x)
li a7, 1
mv a0, %x
ecall
.end_macro
.text
MAIN: #load array address to t0 to start and inizialize t3 to check if element is -1
li t3, -1
la t0, arr
loop:
# load first element of array and if it is zero replace current 0 with next array element and  
# move to check next element if the element is -1 go to print and print the array
lw t1, 0(t0)
beq t1, t3 print
addi t0, t0, 4
bnez t1, loop
lw t2, 4(t0)
mv t1, t2
sw t1, 0(t0)
j loop
print: #print the modified array
la t1, arr
printloop:
lw t2, 0(t1)
print_int (t2)
addi t1, t1, 4
beq t2, t3, exit
j printloop


exit:
li a7, 10
ecall

编辑：我为此编写了一个 C++ 代码：

    #include <iostream>
    
    int main()
    {
      int arr[6]={0,0,2,0,0,-1};
      int arr_temp[6];
      int final_index=0;
      for(int i=0,j=0;i<6;++i)
        {
          if(arr[i]!=0)
        {
          arr_temp[j++]=arr[i];
        }
        }
      for(int i=0;i<6;++i)
        {
          if(arr_temp[i]==-1)
        {
          final_index=i+1;
        }
        }
      for(int i=0;i<final_index;++i)
        {
          arr[i]=arr_temp[i];
        }
      for(int i=0;i<final_index;++i)
        {
          std::cout<<" "<<arr[i]<<" ";
        }
      
    }

我在控制台中得到以下输出： 0220-1 而不是这个： 2-1

关于如何解决这个问题有什么想法吗？

Answer 1

我想我已经解决了问题，感谢评论，我尝试编写 C++ 代码，然后在汇编中编写该代码，我找到了这段代码，它终于按照我想要的方式工作了：

.data
arr: .word 0 0 2 0 0 -1
arrtemp: .space 24
msg: .string " "
.macro print_str (%x)
li a7, 4
la a0, %x
ecall
.end_macro
.macro print_int (%x)
li a7, 1
mv a0, %x
ecall
.end_macro
.text
MAIN:
li t3, -1
la t0, arr # load source array
la t1, arrtemp # load auxilary array
li t4, 6 # array size
li s0, 0


loop: # add non zero elements from source array to auxilary array 
lw t5, 0(t0) 
beq s0, t4, replace
beqz t5, addjump
lw t6, 0(t1)
mv t6, t5
sw t6, 0(t1)
addi t0,t0,4
addi s0, s0, 1
addi t1, t1, 4
j loop
addjump:
addi t0, t0, 4
addi s0, s0, 1
j loop



replace: # overwrite source array with auxilary array
la t0, arr
la t1, arrtemp
li t2, -1
replaceloop:
lw s0, 0(t1)
sw s0, 0(t0)
addi t1, t1, 4
addi t0, t0, 4
beq t2, s0, print
j replaceloop


print: # print modified source array
li t3, -1
la t0, arr2
printloop:
lw t1, 0(t0)
print_int(t1)
addi t0, t0, 4
beq t1, t3, exit
j printloop


exit:
li a7, 10
ecall