以编程方式创建类别和多个子类别

Question

此代码在 WordPress 管理区域中正确显示类别。但不显示子类别。

我需要显示 3 个类别和每个类别 3 个子类别？

这就是我想要的每个类别：

A类

• 子类别1
• 子类别2
• 子类别3

我在WordPress主题的functions.php文件中添加了以下代码：

//create the main category
wp_insert_term(

// the name of the category
'Category A', 

// the taxonomy, which in this case if category (don't change)
'category', 

 array(

// what to use in the url for term archive
'slug' => 'category-a',  
 ));`

然后对于每个子类别：

wp_insert_term(

// the name of the sub-category
'Sub-category 1', 

// the taxonomy 'category' (don't change)
'category',

array(
// what to use in the url for term archive
'slug' => 'sub-cat-1', 

// link with main category. In the case, become a child of the "Category A"   parent  
'parent'=> term_exists( 'Category A', 'category' )['term_id']

));

但我收到错误：

解析错误：解析错误，第 57 行需要 '')'' ...

对应

'parent'=> term_exists( 'Category A', 'category' )['term_id']

。

我做错了什么？

Answer 1

问题是您需要在函数外部获取父项id，以避免错误。您可以轻松地这样做：

$parent_term_a = term_exists( 'Category A', 'category' ); // array is returned if taxonomy is given
$parent_term_a_id = $parent_term_a['term_id']; // get numeric term id

// First subcategory
wp_insert_term(
    'Sub-category 1', // the term 
    'category', // the taxonomy
    array(
        // 'description'=> 'Some description.',
        'slug' => 'sub-cat-1a',
        'parent'=> $parent_term_a_id
    )
);

// Second subcategory
wp_insert_term(
    'Sub-category 2', // the term 
    'category', // the taxonomy
    array(
        // 'description'=> 'Some description.',
        'slug' => 'sub-cat-2a',
        'parent'=> $parent_term_a_id
    )
);

// Third subcategory
wp_insert_term(
    'Sub-category 3', // the term 
    'category', // the taxonomy
    array(
        // 'description'=> 'Some description.',
        'slug' => 'sub-cat-3a',
        'parent'=> $parent_term_a_id
    )
);

然后您将用于其他2组子类别：

// For subcategory group of Category B
$parent_term_b = term_exists( 'Category B', 'category' );
$parent_term_b_id = $parent_term_b['term_id'];

// For subcategory group of Category C
$parent_term_c = term_exists( 'Category C', 'category' );
$parent_term_c_id = $parent_term_c['term_id'];

…以同样的方式（注意为每个子类别都有一个独特的slugs，这意味着总共有9个不同的子类别slugs）… 参考：

Wordpress 函数参考：wp_insert_term
Wordpress 函数参考：term_exists

Answer 2

// the name of the category
'Category A', 

编辑评论：

$parent = term_exists( 'Category A', 'category' );
$termId = $parent['term_id'];

wp_insert_term(

// the name of the sub-category
'Sub-category 1', 

// the taxonomy 'category' (don't change)
'category',

array(
    // what to use in the url for term archive
    'slug' => 'sub-cat-1', 

    // link with main category. In the case, become a child of the "Category A"   parent  
    'parent'=> $termId

));