我是编程的新手,我需要帮助。试着在golang上编写gitlab scraper。当我试图在多线程模式下获取有关项目的信息时,出了点问题。
这是代码:
func (g *Gitlab) getAPIResponce(url string, structure interface{}) error {
responce, responce_error := http.Get(url)
if responce_error != nil {
return responce_error
}
ret, _ := ioutil.ReadAll(responce.Body)
if string(ret) != "[]" {
err := json.Unmarshal(ret, structure)
return err
}
return errors.New(error_emptypage)
}
...
func (g *Gitlab) GetProjects() {
projects_chan := make(chan Project, g.LatestProjectID)
var waitGroup sync.WaitGroup
queue := make(chan struct{}, 50)
for i := g.LatestProjectID; i > 0; i-- {
url := g.BaseURL + projects_url + "/" + strconv.Itoa(i) + g.Token
waitGroup.Add(1)
go func(url string, channel chan Project) {
queue <- struct{}{}
defer waitGroup.Done()
var oneProject Project
err := g.getAPIResponce(url, &oneProject)
if err != nil {
fmt.Println(err.Error())
}
fmt.Printf(".")
channel <- oneProject
<-queue
}(url, projects_chan)
}
go func() {
waitGroup.Wait()
close(projects_chan)
}()
for project := range projects_chan {
if project.ID != 0 {
g.Projects = append(g.Projects, project)
}
}
}
这是输出:
$ ./gitlab-auditor
latest project = 1532
Gathering projects...
.......................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................Get https://gitlab.example.com/api/v4/projects/563&private_token=SeCrEt_ToKeN: unexpected EOF
Get https://gitlab.example.com/api/v4/projects/558&private_token=SeCrEt_ToKeN: unexpected EOF
..Get https://gitlab.example.com/api/v4/projects/531&private_token=SeCrEt_ToKeN: unexpected EOF
Get https://gitlab.example.com/api/v4/projects/571&private_token=SeCrEt_ToKeN: unexpected EOF
.Get https://gitlab.example.com/api/v4/projects/570&private_token=SeCrEt_ToKeN: unexpected EOF
..Get https://gitlab.example.com/api/v4/projects/467&private_token=SeCrEt_ToKeN: unexpected EOF
Get https://gitlab.example.com/api/v4/projects/573&private_token=SeCrEt_ToKeN: unexpected EOF
................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................
每次它都是不同的项目,但它的id大约是550。
当我试图从输出中卷曲链接时,我得到了正常的JSON。当我尝试使用queue := make(chan struct{}, 1)
(单线程)运行此代码时 - 一切都很好。
它能是什么?
我会说这不是一种非常明确的实现并发的方法。这里似乎发生了什么
谈论go concurrency patterns以及这篇博客文章concurrency in go可能有所帮助。我个人很少使用缓冲频道。对于你的问题,我会喜欢: