我想运行列表推导,以在由其他列的值定义的子集中的一列中按'-'对名称进行切片。
在这种情况下:
category product_type name
0 pc unit hero-dominator
1 print unit md-ffx605
2 pc option keyboard1.x-963
我对'pc'类别和'unit'产品类型感兴趣,所以我希望列表理解仅将'name'列的第一行更改为以下形式:
category product_type name
0 pc unit dominator
1 print unit md-ffx605
2 pc option keyboard1.x-963
我尝试过:
df['name'].loc[df['product_type']=='unit'] = [x.split('-')[1] for x in df['name'].loc[df['product_type']=='unit']]
但是我的'列表索引超出范围'IndexError。
非常感谢您的帮助。
您可以通过以下方式解决问题,请关注评论并随时提出问题:
编辑,现在我们考虑在“名称”列中可能没有字符串元素:
import pandas as pd
import numpy as np
def change(row):
if row["category"] == "pc" and row["product_type"] == "unit":
if type(row["name"]) is str: # check if element is string before split()
name_split = row["name"].split("-") # split element
if len(name_split) == 2: # it could be name which does not have "-" in it, check it here
return name_split[1] # if "-" was in name return second part of split result
return row["name"] # else return name without changes
return row["name"]
# create data frame:
df = pd.DataFrame(
{
"category": ["pc", "print", "pc", "pc", "pc", "pc"],
"product_type": ["unit", "unit", "option", "unit", "unit", "unit"],
"name": ["hero-dominator", "md-ffx605", "keyboard1.x-963", np.nan, 10.24, None]
}
)
df["name"] = df.apply(lambda row: change(row), axis=1) # change data frame here
print(df)