nodes 相关问题

节点是用于构建数据结构（如链表和树）的基本单元。

我正在诉诸于stackoverflow的思想，以帮助我确定自己做错了什么。我编写了一个连接到Microsoft Fabric数据库的Nodejs应用程序。我正在使用

const odbc = require('odbc'); async function commitTransaction() { const connection = await odbc.connect(`${process.env.CONNECTION_STRING}`); await connection.beginTransaction(); const insertResult = await connection.query('INSERT INTO MY_TABLE VALUES(1, \'Name\')'); await connection.commit(); // INSERT query has now been committed } commitTransaction();

odbc nodes

回答 0 投票 0

（使用AWS-SDK）如何查找存储在AmazonS3

aws-sdk

amazon-web-services amazon-s3 aws-sdk nodes

回答 1 投票 0

红色黑树的大块节点

def getTradeValue(transaction): return transaction[1] * transaction[2] RED = True BLACK = False class RBTree: def __init__(self, transaction): self.key = getTradeValue(transaction) self.value = [transaction] self.right = None self.left = None self.color = RED def isRed(self): if self is not None: return self.color def rotateLeft(self): rotatedTree = self.right self.right = rotatedTree.left rotatedTree.left = self rotatedTree.color = self.color self.color = RED return rotatedTree def rotateRight(self): rotatedTree = self.left self.left = rotatedTree.right rotatedTree.right = self rotatedTree.color = self.color self.color = RED return rotatedTree def colorFlip(self): self.color = RED self.right.color = BLACK self.left.color = BLACK def put(self, transaction): if self is None: return RBTree(transaction) if getTradeValue(transaction) == self.key: self.value.append(transaction) elif getTradeValue(transaction) < self.key: if self.left is None: self.left = RBTree(transaction) else: self.left.put(transaction) elif getTradeValue(transaction) > self.key: if self.right is None: self.right = RBTree(transaction) else: self.right.put(transaction) if (self.right and self.right.isRed()) and (self.left and not self.left.isRed()): self = self.rotateLeft() if (self.left and self.left.isRed()) and (self.left.left and self.left.left.isRed()): self = self.rotateRight() if (self.left and self.left.isRed()) and (self.right and self.right.isRed()): self.colorFlip() return self def inorder(self): if self: if self.left: print(self.left.inorder()) print(self.key, " ", self.value, " ", self.color) if self.right: print(self.right.inorder()) def print2DUtil(self, space) : COUNT = [10] # Base case if self is None : return # Increase distance between levels space += COUNT[0] # Process right child first if self.right: self.right.print2DUtil(space) # Print current node after space # count print() for i in range(COUNT[0], space): print(end = " ") print(self.key,self.color) # Process left child if self.left: self.left.print2DUtil(space) bst = RBTree(["", 1, 80, ""]) bst.color = BLACK bst = bst.put(["", 1, 9, ""]) bst.color = BLACK # bst.inorder() # print("--------") bst = bst.put(["", 1, 4, ""]) bst.color = BLACK # bst.inorder() bst.print2DUtil(0) print("--------") bst = bst.put(["", 1, 3, ""]) bst.color = BLACK # bst.inorder() bst.print2DUtil(0) print("--------") bst = bst.put(["", 1, 100, ""]) bst.color = BLACK # bst.inorder() bst.print2DUtil(0) print("--------") bst = bst.put(["", 1, 17, ""]) bst.color = BLACK bst.print2DUtil(0) # bst.inorder() print("--------") bst = bst.put(["", 1, 2, ""]) bst.color = BLACK # bst.inorder() bst.print2DUtil(0) print("--------") # bst.print2DUtil(0)

python data-structures binary-search-tree nodes red-black-tree

回答 2 投票 0

如何从lambda（nodejs aws-sdk）获取环境变量

我们可以在AWS-LAMBDA中设置环境变量，例如通过AWS SAM：环境：变量： table_name：！参考表如何通过节点JS AW从当前的lambda获得此变量...

amazon-web-services aws-lambda nodes aws-sdk-nodejs

回答 2 投票 0

在错误类验证器嵌套中包含名称

我想知道是否可能以及如何返回字段名称以及验证错误消息。例子： “信息”： { name: "姓名为必填项", 用户名：“

nestjs nodes nest class-validator

回答 3 投票 0

C++实现双向链表时面临调试问题

我正在实现一个双向链表，其中每个节点都有两个指针。一个指向链表中的下一个节点，另一个指向前一个节点。节点结构由一个整数组成...