projection 相关问题

投影是将一组数据从一种形式转换为另一种形式。

如何实例化并以编程方式应用指令？

angular projection angular-directive angular2-template

回答 3 投票 0

使用Terra Package将栅格数据从地理到投影坐标系转换为预期的结果

I在地理坐标系EPSG中具有栅格数据：4326，单位为单位。我想将我的光栅转换为带有米单元的投影坐标系。我选择 +proj = lcc +l ...

r raster projection terra

回答 1 投票 0

Media投影许可丢失

service media projection foreground

回答 1 投票 0

#include <iostream> #include <vector> #include <stdio.h> #include <GL/glew.h> #include <GLFW/glfw3.h> #include <GLM/glm.hpp> #include <GLM/gtc/matrix_transform.hpp> #include <GLM/gtc/type_ptr.hpp> #include "Window.h" #include "Shader.h" #include "Buffers.h" #include "Camera.h" Window window; std::vector<Buffers*> bufferList; std::vector<Shader> shaderList; static const char* vShader = "Shaders/shader.vert"; static const char* fShader = "Shaders/shader.frag"; void CreateObjects() { GLfloat Cubevertices[] = { 1.0f,1.0f,1.0f, //0 -1.0f,1.0f,1.0f, //1 1.0f,-1.0f,1.0f, //2 -1.0f,-1.0f,1.0f, //3 1.0f,1.0f,-1.0f, //4 -1.0f,1.0f,-1.0f, //5 -1.0f,-1.0f,-1.0f, //6 1.0f,-1.0f,-1.0f, //7 }; unsigned int Cubeindices[] = { 0,1,3, 3,0,2, 3,2,6, 6,7,2, 1,3,5, 5,6,3, 0,1,4, 4,5,1, 2,0,7, 7,4,0, 5,6,4, 4,7,6 }; Buffers* obj1 = new Buffers(); obj1->CreateBuffer(Cubevertices, Cubeindices, 24, 36); //24 36 bufferList.push_back(obj1); } void CreateShaders() { Shader* shader1 = new Shader(); shader1->createFromFiles(vShader, fShader); shaderList.push_back(*shader1); } GLfloat toRad = 3.14159265359f/180.0f; GLfloat r_angle = 0.0f; bool direction = true; float offset = 0.0f; float maxoffset = 0.7f; float inc = 0.0005f; float cursize = 0.5f; bool sizedir = true; int main() { window = Window(500, 500, "Cube"); window.Initialize(); CreateObjects(); CreateShaders(); GLuint u_model = 0, u_project = 0, u_view = 0; glm::mat4 projection = glm::perspective(glm::radians(10.0f), (GLfloat)window.getBufferWidth() / window.getBufferHeight(), 1.0f, 100.0f); while (!window.windowClose()) { glfwPollEvents(); glClearColor(0.0f, 0.0f, 0.0f, 1.0f); glEnable(GL_DEPTH_TEST); glClear(GL_COLOR_BUFFER_BIT|GL_DEPTH_BUFFER_BIT); shaderList[0].UseShader(); u_model = shaderList[0].getUniformModelLocation(); u_project = shaderList[0].getProjectionModelLocation(); glm::mat4 model(1.0f); //TRANSLATION if (direction) { offset += inc; } else { offset -= inc; } if (abs(offset) >= maxoffset) { direction = !direction; } model = glm::scale(model, glm::vec3(0.3f, 0.3f, 0.3f)); model = glm::translate(model, glm::vec3(0.0f, offset, 0.0f)); model = glm::rotate(model, toRad*45.0f, glm::vec3(1.0f, 1.0f, 1.0f)); glUniformMatrix4fv(u_project, 1, GL_FALSE, glm::value_ptr(projection)); glUniformMatrix4fv(u_model, 1, GL_FALSE, glm::value_ptr(model)); bufferList[0]->Render(); window.swapBuffers(); } return 0; }

c++ opengl projection perspective

回答 0 投票 0

我在多场结构上有一个范围。

#include <ranges> #include <algorithm> using namespace std; enum Direction { HORIZONTAL, VERTICAL }; struct Maille { int16_t i, j; int16_t& operator[](Direction input_direction) { switch (input_direction) { case HORIZONTAL: return j; case VERTICAL: return i; } } int16_t operator[](Direction input_direction) const { switch (input_direction) { case HORIZONTAL: return j; case VERTICAL: return i; } } }; int main() { Maille tab[2]={ {.i=1,.j=2}, {.i=2,.j=1} }; for (Maille& m : tab) { if (m[HORIZONTAL]==1) m[HORIZONTAL]=4; } ranges::replace(tab | views::transform([](Maille& m){ return m[HORIZONTAL];}),1,4); return 0; }

c++ replace c++20 projection c++23

回答 0 投票 0

MTGLightning AFA数据图

python plot projection cartopy netcdf4

回答 0 投票 0

沿所有坐标轴查找点到（超）平面的投影

我有一组线性回归问题，其维度从 2D（拟合到单个自变量的线）到 3D（拟合到两个自变量的平面）再到 nD，其中 hyperpl...

r linear-regression projection

回答 1 投票 0

openlayers -OS休闲层

openlayers layer projection xyz

回答 1 投票 0